Question #167154

A person has agreed to participate in an extrasensory perception (ESP) experiment. He is asked to randomly pick two numbers between 1 and 6 (inclusive). In addition, the second number must be different from the first. Let H = event the first number picked is a 3. K = event the second number picked exceeds 4.

(a) Find P(H).

(b) Find P(K|H). Hint: given that the 1st number is 3, what numbers are left for the man to select from? (c) Find P(K & H). Hint: use the multiplication rule. Are these events independent?

(d) Find the probability that both numbers picked is less than 3. Hint: redefine H and K appropriately and follow the same pattern as parts (a)-(c). 


1
Expert's answer
2021-03-02T01:04:32-0500

a)

P(H)=16P(H)=\dfrac{1}{6}

b)

P(KH)=25P(K|H)=\dfrac{2}{5}

c)


P(KH)=16(25)=115P(KH)=\dfrac{1}{6}(\dfrac{2}{5})=\dfrac{1}{15}

d)


P(both<3)=26(15)=115P(both<3)=\dfrac{2}{6}(\dfrac{1}{5})=\dfrac{1}{15}



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