A couple is planning to have three children.What is the probability that?
There are 8 possible arrangements of girls and boys. For example, GGB means the first two children are girls and the third child is a boy. All 8 arrangements are (approximately) equally alike.
The possible arrangements are:
GGG
GGB
GBG
GBB
BGG
BGB
BBG
BBB
Assume that the probability for aither B or G is "\\frac{1}{2}"
So, the probability of any of these arrangements is:
"\\frac{1}{2} \\times \\frac{1}{2} \\times \\frac{1}{2} = \\frac{1}{8}"
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