the time for a major exam to be completed is normally distributed with an average of 55 minutes and a standard deviation of 9 minutes. If 92% of the student completed the exam, when should the test be terminated?
Having a normal distribution with parameters "\\mu" = 55 and "\\sigma" = 9 we need to find the time T: P(t < T) = 0.92 . The same is to find T' = (T - "\\mu") / "\\sigma" , which is the 0.92 quantile of normal distribution with parameters "\\mu" = 0 and "\\sigma" = 1. So T' = 1.41 and T = "\\sigma" *T' + "\\mu" = 9*1.41 + 55 = 67.69.. The test should be terminated after 67.7 minutes.
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