Question

4 out of 12 television set chosen at of random are defentive, if three of the tv set are choosen at of random for shipment to a hotel, how many defective set can they expect

Answer 1

Probability of choosing defective televisions is (p)$= \dfrac{4}{12}= \dfrac{1}{3}$

Number of televisions that are choose for shipment to a hotel(n) = 3

So, the number of defective set they can expect= $n\times p=3\times \dfrac{1}{3}=1$

Hence they should expect 1 defective television.