Answer to Question #165124 in Statistics and Probability for Sahil Guptta

Question

An unbiased die is thrown find out the probability of getting

Prime number

Odd number

Even number

A multiple of 2&3

Number less than 7

A multiple of 4 ?

Answer 1

Solution:

1) Prime numbers on a die are 1, 2, 3, 5; there are 4 in total:

$P(pr) = \frac{4}{6}=\frac{2}{3}=0.(6)$

2) Odd numbers on a die are 1, 3, 5; there are 3 in total:

$P(odd) = \frac{3}{6}=0.5$

3) Even numbers on a die are 2, 4, 6; there are 3 in total:

$P(even) = \frac{3}{6} = 0.5$

4) There is no 0 on a die, so:

$P(0) = 0$

5) Multiple of 2 and 3 is only 6:

$P(mul 2,3)= \frac{1}{6} = 0.1(6)$

6) All of the numbers on a die are less than 7:

$P(x<7) = 1$

7) The only multiple of 4 on a die is 4:

$P(4) = \frac{1}{6} = 0.1(6)$

Answer:

1) $0.(6)$

2) $0.5$

3) $0.5$

4)

5) $0.1(6)$

6) $1$

7) $0.1(6)$