A magic bag contains of 10 good articles, 4 with minor defects and 2 with major
defects. Two articles are chosen from the magic bag at random. Find the
probability [5]
(a) Exactly 1 is good
(b) Neither is good
(c) Both has major defects
1
Expert's answer
2021-02-24T06:08:45-0500
There are two places, where 10 appropriate variants for the first place and 6 for the second, so 10 * 6 = 60 all variants. It's necessary to divide by all possible variants - 16*15/2 (16 variants on the first place and 15 on the second, because one article is occupied on the first place, after that divide by 2 because the order is not important). The probability is equal to (10*6)/(16*15/2) = 1/2
There are 16-10 = 6 articles, which have minor or major defects. So we have 6*5 = 30 variants to choose "minor or major" articles and 16*15/2 = 150 all variants. The probability is equal to (6*5)/(16*15/2) = 1/4
Obviously, there is only one appropriate variant to choose two "major" articles. And also 150 all possible variants. The probability is equal to 1/150
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