Q2: Group Frequency
The length, in mm, of 48 rubber tree leaves are given below:
137 152 127 147 141 157 132 153 166 147 136 134
146 142 162 169 149 135 166 157 141 146 147 148
163 133 148 150 136 127 162 152 143 138 142 153
145 154 144 126 139 126 158 147 136 144 159 161
Create a group frequency table for this data using sturge’s rule as a guide to find the number of intervals
Q3: Group Frequency
A Statistics test is marked out of 60. Here are the marks for the 65 students:
26 11 21 35 44 23 37 26 11 21 35 44 23
37 26 11 21 35 44 23 37 16 42 11 47 59
45 16 13 18 16 42 11 47 59 45 16 13 18
16 42 11 47 59 45 16 13 18 19 25 15 32
54 8 38 42 53 19 25 15 32 54 8 38 42
a. Construct a grouped frequency table for the data using the 2 to k rule as guide to find the number of intervals.
b. What percentages of the class scored above 40 marks?
Q4: Simple Frequency and Bar Chart
James asked his friends their favourite colours. They mention
Green Blue Red Green Blue Blue Green
Red Blue White Blue Green Red Green
Blue Red Blue Green Red Green
a. Construct a frequency table for the favourite colour data
b. Represent the information on a bar chart
Q2
n = 48
Sturge's rule: the number of groups or classes is k = 1 + 3.322 log(n)
Thus k = 1 + 3.322 log48 = 7
the lowest value is 126
the highest value is 169
range R = the highest value – the lowest value = 169 – 126 = 43
the class width = "\\frac{R}{k}=\\frac{43}{7}=6"
thus we have:
Q3
n = 65
According to 2k rule, 2k > n, where k is the number of classes and n is the number of data points.
2k > 65
Therefore the number of classes is k = 7
the lowest value is 8
the highest value is 59
range R = the highest value – the lowest value = 59 – 8 = 51
the class width = "\\frac{R}{k}=\\frac{51}{7}=7"
thus we have:
What percentages of the class scored above 40 marks?
There are 20 students that scored above 40 marks thus:
"\\frac{20}{65}\\cdot100\\%=31\\%"
Q4
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