Answer to Question #163885 in Statistics and Probability for Greyce

Question #163885

A principal at a certain school claims that the students in his school are above average intelligence. A random sample of thirty students IQ scores have a mean score of 112. Is there sufficient evidence to support the principal’s claim? The mean population IQ is 100 with a standard deviation of 15.


1
Expert's answer
2021-02-24T06:59:24-0500

We have that

"n=30"

"\\bar x=112"

"\\mu = 100"

"\\sigma=15"

"H_0: \\mu=100"

"H_a:\\mu>100"

The hypothesis test is right-tailed.

The population standard deviation is known and the sample size is large (n≥30) so we use z-test.

Let the significance level be 5% in this test, therefore Z0.05 = 1.64

The critical region is Z > 1.64

Test statistic:


"Z_{test}=\\frac{\\bar x -\\mu}{\\frac{\\sigma}{\\sqrt n}}=\\frac{112 -100}{\\frac{15}{\\sqrt {30}}}=4.38"

Since 4.38 > 1.64 thus the Ztest falls in the rejection region we reject the null hypothesis.

At the 5% significance level the data do provide sufficient evidence to support the claim. We are 95% confident to conclude that the students in the school are above average intelligence.


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Comments

Assignment Expert
15.07.21, 23:37

Dear bach, "H_0" can be expressed as "\\mu=100" or "\\mu\\leq 100."


bach
27.06.21, 16:45

why H0 is just u = 100 but not u

Assignment Expert
29.04.21, 19:57

Dear Zohaib khan, please use the panel for submitting new questions.

Zohaib khan
29.04.21, 14:21

A psychologist examined the effect of chronic alcohol abuse on memory. In this study, a standardized memory test was used. Scores on this test for the general population from a normal distribution with µ=50 and ϭ=6. A random sample n=22 people diagnosed with alcohol abuse had a mean score of mean is 47. Is there evidence for memory impairment among people diagnosed with alcohol abuse? Use α=0.05 Explain whether you reject or accept the null hypothesis.

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