let S−number of all aircraft departures
S=105+15+38+20+21+7+200+59=465
let Sd−number of all delayed aircraft departures
Sd=15+20+7+59=101
delayed departure probability:
Pd=SSd=465101
probability of delayed company D flight
Pd(D)=SdSd(D)=10159
the probability that the flight is delayed and serviced by company D:
Pd∗Pd(D)=465101∗10159≈0,1269
Answer:≈0,1269
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