Answer to Question #163802 in Statistics and Probability for Zafar

Question

A company runs a corporate event which offers a total of three identical lucky door prizes of tablet computers. Each person who purchases a ticket and attends the event has an equal chance of winning and can only win one tablet.

If 991 people attend the event and three are chosen to win tablets, in how many ways can the tablets be distributed?

Give your answer to the nearest integer entering numbers only.

Answer 1

$N=C_{991}^3=\frac{991!}{(991-3)!3!}=161716315$