Question #163429

Recall the example of rolling a six-sided die. This is an example of a discrete uniform random variable, so named because the probability of observing each distinct outcome is the same, or uniform, for all outcomes. Let Y be the discrete uniform random variable that equals the face-value after a roll of an eight-sided die. (The die has eight faces, each with number 1 through 8.) Calculate E(Y ), Var(Y ), and Standard Deviation (Y )


1
Expert's answer
2021-02-22T12:33:09-0500

Since Each face is likely to occur

So probability of getting each face =18=\dfrac{1}{8}


The Probability Distribution for the 8-faces die is-




Mean is given by-

E(Y)=xipi=(1×18)+(2×18)+(3×18)+(4×18)+(5×18)+(6×18)+(7×18)+(8×18)E(Y)=\sum x_ip_i=(1\times\dfrac{1}{8})+(2\times\dfrac{1}{8})+(3\times\dfrac{1}{8})+(4\times\dfrac{1}{8})+(5\times\dfrac{1}{8})+(6\times\dfrac{1}{8})+(7\times\dfrac{1}{8})+(8\times\dfrac{1}{8})


=1+2+3+4+5+6+7+88=368=4.5\dfrac{1+2+3+4+5+6+7+8}{8}=\dfrac{36}{8}=4.5


Varaince is calculated by the formula-

V(Y)=(xixˉ)2NV(Y)=\dfrac{\sum(x_i-\bar{x})^2}{N}


=(3.5)2+(2.5)2+(1.5)2+(0.5)2+(0.5)2+(1.5)2+(2.5)2+(3.5)28\dfrac{(3.5)^2+(2.5)^2+(1.5)^2+(0.5)^2 +(-0.5)^2+(-1.5)^2+(-2.5)^2+(-3.5)^2}{8}


=12.25+6.25+2.25+0.25+0.25+2.25+6.25+12.258\dfrac{12.25+6.25+2.25+0.25+0.25+2.25+6.25+12.25}{8}


=428=5.25\dfrac{42}{8}=5.25


Standard deviation is given by-


S(Y)=V(Y)=5.25=2.29S(Y)=\sqrt{V(Y)}=\sqrt{5.25}=2.29


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