2.1. Let P(A) = 0.5, P(B) = 0.6 and P(A ∩ B) = 0.3. Find P(B¯), P(A ∩ B¯) and P(A ∪ B)
P(B‾)=1−P(B)=0.4P(A∩B‾)=P(A)−P(A∩B)=0.2P(A∪B)=P(A)+P(B)−P(A∩B)=0.8P(\overline{B})=1-P(B)=0.4\\ P(A\cap \overline{B})=P(A)-P(A\cap B)=0.2\\ P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.8P(B)=1−P(B)=0.4P(A∩B)=P(A)−P(A∩B)=0.2P(A∪B)=P(A)+P(B)−P(A∩B)=0.8
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