Solution:
First, we need to find the cost for each day, using formula: f(x)=10x+100 , where x is the number of days. Calculating it for each day, we get the following distribution:
{ξp(ξ)}={1100.041200.211300.341400.311500.1}
Remembering the formula for variance:
var(ξ)=E(ξ2)−(E(ξ))2 ,
we also need to find distribution for E(ξ2) :
{ξ2p(ξ2)}={12100.0414400.2116900.3419600.3122500.1}
Next:
E(ξ)=0.04∗110+0.21∗120+0.34∗130+0.31∗140+0.1∗150=132.2
E(ξ2)=0.04∗12100+0.21∗14400+0.34∗16900+0.31∗19600+0.1∗22500=17580
And we geat the answer:
var(ξ)=E(ξ2)−(E(ξ))2=17580−(132.2)2=103.16
Answer:
var(ξ)=103.16
Comments
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Thanks so very much experts for this solution. It was really a puzzle to me and now i get it with better understanding after attentively going through your steps.