In six attempts it took a locksmith 9, 14, 7, 8 11, 5 seconds to open a certain kind of lock. Construct a 95% confidence interval for the average it takes the locksmith to open this kind of lock.
"\\bar{x} = \\frac{9 + 14 +7+8+11+5}{6} \\\\\n\n= 9"
Standard deviation
"SD = 3.1623 \\\\\n\nn = 6"
Degree of freedom
"df = n - 1 \\\\\n\n= 6 - 1 \\\\\n\n= 5"
we look into t-distribution table with df and with 95% confidence level
Critical value t = 2.571
Confidence interval formula:
"= \\bar{x} \u00b1 \\frac{t \\times SD}{\\sqrt{n}} \\\\\n\n= 9 \u00b1 \\frac{2.571 \\times 3.1623}{\\sqrt{6}} \\\\\n\n= 9 \u00b1 3.32 \\\\"
5.68 < μ < 12.32
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