Given a normal distribution with a standard deviation of 14, what is the mean if 40% of the values are below 60?
We have that
σ=14\sigma = 14σ=14
P(X<60)=0.4P(X<60)=0.4P(X<60)=0.4
P(X<60)=P(Z<60−μσ)=0.4P(X<60)=P(Z<\frac{60 - \mu}{\sigma})=0.4P(X<60)=P(Z<σ60−μ)=0.4
Z-value of –0.25 corresponds to 40% of the area under the curve.
Then
60−μσ=−0.25 ⟹ μ=60+0.25⋅σ=60+0.25⋅14=63.5\frac{60-\mu}{\sigma}=-0.25 \implies \mu=60+0.25\cdot\sigma=60+0.25\cdot14=63.5σ60−μ=−0.25⟹μ=60+0.25⋅σ=60+0.25⋅14=63.5
Answer: the mean is 63.5
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