A company tested 735 of the lightbulbs they produced and found them to have a mean life of 1,200 hours and a standard deviation of 50 hours. How many of these lightbulbs had a life between 1,170 hours and 1,230 hours?
We assume that the distribution of the values of life of the lightbulbs can be well approximated by a normal distribution with the same parameters: mean 1,200 hours and standard deviation 50 hours.
Then the value of life is equal to 1200 + 50X, where X is a standard normally distributed random variable. The probability that the value of life is between 1,170 and 1,230 hours is equal to the probability that the value of X is between -0.6 and 0.6:
"1170 \\leq 1200 + 50X \\leq 1230"
"(1170-1200)\/50 \\leq X \\leq (1230-1200)\/50"
"-0.6\\leq X \\leq 0.6"
This probability may be found as the integral
"\\frac{1}{\\sqrt{2\\pi}}\\int\\limits_{-0.6}^{0.6}e^{-x^2\/2}dx = \\Phi(0.6) -\\Phi(-0.6) =0.72575 - 0.27425 = 0.4515"
where "\\Phi(x) = \\frac{1}{\\sqrt{2\\pi}}\\int\\limits_{-\\infty}^{x}e^{-t^2\/2}dt" - the cumulative distribution function of the standard normal distribution, its values we may get from the tables.
The estimated number of lightbulbs had a life between 1,170 hours and 1,230 hours is equal to "735 \\cdot 0.4515 = 331.85"
Answer. The estimated number of lightbulbs had a life between 1,170 hours and 1,230 hours is equal to 331.85.
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