A machine operates without a breakdown in 90% of the times on a given day. What is the probability that in one week of 6 working days there are at most 3 breakdowns that occur?
Select one:
0.9841
0.0159
0.9987
0.0013
Clear my choice
Here we have that
P(machine operates without a breakdown) = 0.9
Hence P(breakdown) = 1 – 0.9 = 0.1
n = 6
x = 3
The number of breakdowns that occur among a fixed number of trials follows the binomial distribution.
The binomial distribution formula:
The probability that in one week of 6 working days there are at most 3 breakdowns that occur:
Answer:
The probability that in one week of 6 working days there are at most 3 breakdowns that occur is 0.9987
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