Question #155425

suppose the mean weight of all the students in this examination hall is 54 kgs, and the standard deviation is 4 kgs. what percentage of students will fall between 44 to 62 kgs? justify your answer


Expert's answer

Let XX be the weight of student. If the distribution of XX is not normal we cannot say about the percentage of students will fall between 44 to 62 kgs.

If we assume that the weight of student is normally distributed than XN(μ,σ2)X\sim N (\mu, \sigma^2).


Z=XμσN(0,1)Z=\dfrac{X-\mu}{\sigma}\sim N(0, 1)

Given μ=54,σ=4.\mu=54, \sigma=4.


P(44<X<62)=P(X<62)P(X44)P(44<X<62)=P(X<62)-P(X\leq 44)

=P(Z<62544)P(Z44544)=P(Z<\dfrac{62-54}{4})-P(Z\leq\dfrac{44-54}{4})

=P(Z<2)P(Z2.5)=P(Z<2)-P(Z\leq-2.5)

0.977250.00621=0.97104\approx0.97725-0.00621=0.97104

97.104 % of students will fall between 44 to 62 kgs.



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