a. Find the probability of success that the proportion of success in a sample of 500 is less than 22% .
The probability of success for any trail of a binomial experiment is, p=0.25.
The sample size, n = 500
The probability of success that the proportion of success in a sample of 500 is less than 22% is,
"P(\\bar{P}<0.22)=P( \\frac{\\bar{P}-p}{\\sqrt{\\frac{p(1-p)}{n}}}<\\frac{0.22-0.25}{\\sqrt{\\frac{0.25(1-0.25)}{500}}} ) \\\\\n\n=P(Z<\\frac{0.22-0.25}{0.0194} \\\\\n\n=p(Z<-1.55) \\\\\n\n= 0.0606"
Therefore, the probability of success that the proportion of success in a sample of 500 is less than 22% is 0.0606.
b. Find the probability of success that the proportion of success in a sample of 800 is less than 22% .
The probability of success for any trail of a binomial experiment is, p=0.25.
The sample size, n=800
The probability of success that the proportion of success in a sample of 800 is less than 22% is,
"P(\\bar{P}<0.22)=P( \\frac{\\bar{P}-p}{\\sqrt{\\frac{p(1-p)}{n}}}<\\frac{0.22-0.25}{\\sqrt{\\frac{0.25(1-0.25)}{800}}} ) \\\\\n\n=P(Z<\\frac{0.22-0.25}{0.0153} \\\\\n\n=p(Z<-1.96) \\\\\n\n= 0.0250"
Therefore, the probability of success that the proportion of success in a sample of 800 is less than 22% is 0.0250.
c. Find the probability of success that the proportion of success in a sample of 1000 is less than 22%.
The probability of success for any trail of a binomial experiment is, p=0.25.
The sample size, n=1000
The probability of success that the proportion of success in a sample of 1000 is less than 22% is,
"P(\\bar{P}<0.22)=P( \\frac{\\bar{P}-p}{\\sqrt{\\frac{p(1-p)}{n}}}<\\frac{0.22-0.25}{\\sqrt{\\frac{0.25(1-0.25)}{1000}}} ) \\\\\n\n=P(Z<\\frac{0.22-0.25}{0.0137} \\\\\n\n=p(Z<-2.19) \\\\\n\n= 0.0143"
Therefore, the probability of success that the proportion of success in a sample of 1000 is less than 22% is 0.0143.
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