Question #146916

A continuous random variable has a density function𝑓(π‘₯) = 2(5 – x) 5 , where 2<x<3. Calculate the following probability correct up to 3 decimal places, and make the graph for part (a) only in Answer sheet:

P (x < 2.5)

P (x > 2.2)

P (2.1 ≀ π‘₯ ≀ 2.7)


1
Expert's answer
2020-11-30T13:34:45-0500

I) p(x<2.5)= ∫22.52β‹…(5βˆ’x)5 dx\displaystyle\int\limits^{{2.5}}_{{2}} 2\cdot\dfrac{(5-x)}{5}\,{{d}x}


= ∫22.52dxβˆ’βˆ«22.52x5dx\int_{2}^{2.5}2dx-\int_{2}^{2.5}\frac{2x}{5}dx


=2xβˆ’x25∣2to2.5=2x-\frac{x^2}{5}| 2 to 2.5

=1120=\frac{11}{20}


ii)∫2.232β‹…(5βˆ’x)5 dx\displaystyle\int\limits^{{3}}_{{2.2}} 2\cdot\dfrac{(5-x)}{5}\,{{d}x}


∫2.232dxβˆ’βˆ«2.232x5dx\int_{2.2}^{3}2dx-\int_{2.2}^{3}\frac{2x}{5}dx


=96125=\frac{96}{125}


iii)∫2.12.72β‹…(5βˆ’x)5 dx\displaystyle\int\limits^{{2.7}}_{{2.1}} 2\cdot\dfrac{(5-x)}{5}\,{{d}x}


∫2.12.72dxβˆ’βˆ«2.12.72x5dx\int_{2.1}^{2.7}2dx-\int_{2.1}^{2.7}\frac{2x}{5}dx


=78125=\dfrac{78}{125}




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