I) p(x<2.5)= 2β«2.5β2β
5(5βx)βdx
= β«22.5β2dxββ«22.5β52xβdx
=2xβ5x2ββ£2to2.5
=2011β
ii)2.2β«3β2β
5(5βx)βdx
β«2.23β2dxββ«2.23β52xβdx
=12596β
iii)2.1β«2.7β2β
5(5βx)βdx
β«2.12.7β2dxββ«2.12.7β52xβdx
=12578β
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