Maybe more than 1000 but not less than 1350:
P(1000<X<1350)=P(X<1350)−P(X<=1000)=F((1350−1200)/102)−F((1000−1200)/102)=F(1.4706)−F(−1.9608)=0.9293−0.0250=0.9043P(1000<X<1350) = P(X<1350) - P(X<=1000) = F((1350-1200)/102) - F((1000-1200)/102) = F(1.4706) - F(-1.9608) = 0.9293 - 0.0250 = 0.9043P(1000<X<1350)=P(X<1350)−P(X<=1000)=F((1350−1200)/102)−F((1000−1200)/102)=F(1.4706)−F(−1.9608)=0.9293−0.0250=0.9043
Answer: 0.9043
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