We have that μ=10,σ=2\mu=10, \sigma=2μ=10,σ=2
P(X≤x)=P(Z≤x−μσ)=0.03P(X\leq x)=P(Z\leq \frac{x-\mu}{\sigma})=0.03P(X≤x)=P(Z≤σx−μ)=0.03
Z-value of –1.88 to 3% of area under the curve. Then
x−μσ=x−102=−1.88\frac{x-\mu}{\sigma}=\frac{x-10}{2}=-1.88σx−μ=2x−10=−1.88
Solve for x
x=10−2⋅1.88=6.24x=10-2\cdot1.88=6.24x=10−2⋅1.88=6.24
Answer: 6.24 years.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments