Whats to odds of picking the 1st 2nd and 3rd place car in order in a 43 car field?
1
Expert's answer
2012-09-04T11:34:01-0400
Dear visitor Unfortunately, the statement of your question is a bit confusing. What do you need to be done? Please, give us the details so we could help you
There is only one variant that fits us and combintanions of 3 out of
43 =43!/(3!*40!)=12341 is all possible variants. So the odds of picing
the exact three cars are 12340:1.
robert harriss
05.09.12, 01:10
Sorry ,,Let me explain myself better.. Im am looking for what the
odds/probability IE: (34652 to 1) odds are to pick the 1st ,2nd and
3rd. place car in a nascar race,, there are 43 cars running that
race...
Comments
There is only one variant that fits us and combintanions of 3 out of 43 =43!/(3!*40!)=12341 is all possible variants. So the odds of picing the exact three cars are 12340:1.
Sorry ,,Let me explain myself better.. Im am looking for what the odds/probability IE: (34652 to 1) odds are to pick the 1st ,2nd and 3rd. place car in a nascar race,, there are 43 cars running that race...