Question #13628

a problem is given to three students a b and c whose chances of solving the problem is 1/3 , 1/4 and 1/5 repesctively. find the probability that the problem will be solved by at least one of them

Expert's answer

Question #13628

a problem is given to three students a b and c whose chances of solving the problem is 1/31/3, 1/41/4 and 1/51/5 repesctively. find the probability that the problem will be solved by at least one of them.

**Solution.** Denote by A1,A2,A3A_{1}, A_{2}, A_{3} respectively events that students a,b,c, will solve. Then A1,A2,A3A_{1}, A_{2}, A_{3} are independent and P(A1=1/3)P(A_{1} = 1/3), P(A2)=1/4P(A_{2}) = 1/4, P(A3=1/5)P(A_{3} = 1/5). The event (the problem will be solved by at least one of them) is opposite to the (none of them will solve the problem), thus the probability in question equals 1(11/3)(11/4)(11/5)=12/33/44/5=3/51 - (1 - 1/3)(1 - 1/4)(1 - 1/5) = 1 - 2/3 \cdot 3/4 \cdot 4/5 = 3/5.

**Answer.** 3/53/5.

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