Question #139221
The lifetimes of the light bulbs produced by Filip Company are normally distributed with a mean of 1,150 hours and a standard deviation of 175 hours.

What is the probability that a randomly chosen light bulb will have a life time of more than 1000 hours?
What percentage of the light bulbs would be expected to last between 1000 and 1500?
1
Expert's answer
2020-10-21T15:08:54-0400

μ=1150\mu=1150

σ=175\sigma=175

P(X>1000)=1P(X<1000)=1P(Z<1000μσ)=P(X>1000) = 1-P(X<1000)=1-P(Z<\frac{1000-\mu}{\sigma})=

=1P(Z<10001150175)=1P(Z<0.86)=10.1949=0.8051=1-P(Z<\frac{1000-1150}{175})=1-P(Z<-0.86)=1-0.1949=0.8051


Answer: the probability that a randomly chosen light bulb will have a life time of more than 1000 hours is 0.8


P(1000<X<1500)=P(1000<X<1500)=P(1000<X<1500)=P(1000<X<1500)=

=P(1000μσ<Z<1500μσ)==P(\frac{1000-\mu}{\sigma}<Z<\frac{1500-\mu}{\sigma})=

=P(10001150175<Z<15001150175)=P(0.86<Z<2)==P(\frac{1000-1150}{175}<Z<\frac{1500-1150}{175})=P(-0.86<Z<2)=

=P(Z<2)P(Z<0.86)=0.97720.1949=0.7823=P(Z<2)-P(Z<-0.86)=0.9772-0.1949=0.7823


Answer:  78.23% of the light bulbs would be expected to last between 1000 and 1500


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Comments

Assignment Expert
18.12.20, 19:23

Dear JG, please use the panel for submitting new questions.

JG
18.12.20, 17:38

A survey was conducted among some first graders and one of the questions was how much money they spent on their school cafeteria. The random variable x represents the amount of money spent on a particular day with the corresponding probability P(X). x 1 3 5 10 20 P(X) 0.16 ? 0.22 0.22 0.08 a) What is the probability that a 1st grader spends exactly 3 dollars? b) Calculate the expected value, variance and standard deviation of the random variable X?

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