μ=1150
σ=175
P(X>1000)=1−P(X<1000)=1−P(Z<σ1000−μ)=
=1−P(Z<1751000−1150)=1−P(Z<−0.86)=1−0.1949=0.8051
Answer: the probability that a randomly chosen light bulb will have a life time of more than 1000 hours is 0.8
P(1000<X<1500)=P(1000<X<1500)=
=P(σ1000−μ<Z<σ1500−μ)=
=P(1751000−1150<Z<1751500−1150)=P(−0.86<Z<2)=
=P(Z<2)−P(Z<−0.86)=0.9772−0.1949=0.7823
Answer: 78.23% of the light bulbs would be expected to last between 1000 and 1500
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A survey was conducted among some first graders and one of the questions was how much money they spent on their school cafeteria. The random variable x represents the amount of money spent on a particular day with the corresponding probability P(X). x 1 3 5 10 20 P(X) 0.16 ? 0.22 0.22 0.08 a) What is the probability that a 1st grader spends exactly 3 dollars? b) Calculate the expected value, variance and standard deviation of the random variable X?