Solution
Mean
Mean,xˉ=∑f∑fx=1004560=45.6 Ans: 45.6
Median
Median=L+fh(2N−cf) where; L= lower limit of the median class, h=class width of median class, f=frequency of median class, N=total frequency, cf= cum. frequency above median class.
2100=50 , hence the age of the 50th person is the median. median class is between 36-45
∴Median=35.5+2210(2100−30)=44.590 Ans: 44.590
Mode
Mode=L+(2f1−f0−f2f1−f0)iwhere; L = lower limit of modal class
f1= frequency of the modal group,
f0=frequency of the group before modal group
f2= frequency of group after the modal group
i= class width of modal group
36-45 is the modal group since it has the highest frequency.
Mode=35.5+(2(22)−18−1922−18)10=41.2143
Ans: 41.2143
Comments
Leave a comment