solution
Part a)
"p = \\frac{280}{500}= \\frac{14}{25}=0.56"
answer: 0.56
part b)
At a "99\\%" level of confidence, the test statistic "Z= 2.576"
Standard deviation "\\sigma = \\sqrt \\frac{p(1-p)}{n}"
"\\sqrt \\frac{0.56(1-0.56)}{500}=0.0222"
The confidence interval:
answer: "[50.28\\%, 61.72\\%]"
Part c)
"\\hat p=0.6"
"\\frac{0.56-0.6}{\\sqrt \\frac{0.6(1- 0.6)}{500}\n}=-1.876"
At a 95% level of confidence, the rejection region is "|Z|>1.96"
answer: since "|-1.876| \\not >1.96" we fail to reject the hypothesis. There is no evidence to refute the claim
Part d)
From part b), we fail to reject the claim if it is within the confidence limits i.e.
"[50.28\\%, 61.72\\%]"
Answer: We fail to reject the claim since 0.6 is within the acceptance region
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