Hypothesis H0 : µ =30 vs H1 < 30
Then we go ahead test the hypothesis
we first calculate the standard deviation and mean from the given values.
mean = 28.6, standard deviation = 2.76 and standard error = 0.976.
t = (x-µ)/(∂/√n) = (30-28.6)/(2.76/√8) = (1.4/0.976)= 1.43 we calculate from t tables p-value of t 1.43, d f =7,p-value =0. 0979 thus since the p-value is greater than given significance of 0.01 we fail to reject null hypothesis and conclude that the average rainfall is not less than 30.
Comments
Leave a comment