Question #133145
In a recent sample of 85 used cars sales costs, the sample mean was $6,925 with a standard deviation of $3,159. Assume the underlying distribution is approximately normal.
a. what is the random x variable
b.Construct a 95% confidence interval for the population mean cost of a used car.
(i) State the confidence interval. (Round your answers to one decimal place.)
sketch the graph a/2= CL=
Calucate error bound
1
Expert's answer
2020-09-15T17:27:00-0400

Let  the random variable XX be the cost of a used car.

The provided sample mean is Xˉ=6925\bar{X}=6925 and the sample standard deviation is s=3159.s=3159. The size of the sample is n=85n=85 and the required confidence level is 95%.

The number of degrees of freedom are df=851=84,df=85-1=84, and the significance level is α=0.05.\alpha=0.05.

Based on the provided information, the critical t-value for α=0.05\alpha=0.05 and df=84df=84

degrees of freedom is tc=1.9886.t_c=1.9886. The 95% confidence for the population μ\mu  is computed using the following expression


CI=(Xˉtc×sn,Xˉ+tc×sn)=CI=(\bar{X}-\dfrac{t_c\times s}{\sqrt{n}}, \bar{X}+\dfrac{t_c\times s}{\sqrt{n}})=

=(69251.9886×315985,6925+1.9886×315985)==(6925-\dfrac{1.9886\times 3159}{\sqrt{85}}, 6925+\dfrac{1.9886\times 3159}{\sqrt{85}})=

=(6243.62,7606.38)=(6243.62, 7606.38)

EBM=tc×sn=1.9886×315985=681.38EBM=\dfrac{t_c\times s}{\sqrt{n}}=\dfrac{1.9886\times 3159}{\sqrt{85}}=681.38



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