The expected value of one ticket is given by,
The probability of winning the prize * net prize value + The probability of losing the prize * cost of one ticket
"= \\frac {1}{1000}*(1000-1)+\\frac{999}{1000}*(-1)=\\frac {999}{1000}-\\frac {999}{1000}=0"
Hence the expected value of one ticket = $0
Comments
Leave a comment