a)
10%/100%=1/10,
1/10"\\cdot"40=4 red balls in the bag A.
40-4=36 blue balls in the bag A.
30%/100%=3/10
3/10⋅10=3 red balls in the bag B.
10-3=7 blue balls in the bag B.
Let A be the event of having a red ball eventually.
Let B be the event that the ball was taken at random from Bag A is red.
Then
P(A)=P(A|B)P(B)+P(A|"\\overline{B}")P("\\overline{B}" )
P(B)=m/n
4 red balls in the bag A, so m=4.
Bag A consists of 40 balls, so n=40.
P(B)=4/40=1/10,
P("\\overline{B}")=1-P(B)=1=1/10=9/10.
P(A|B)=m/n,
3 red balls in the bag B, so m=3+1=4.
Bag B consists of 10 balls, so n=10+1=11.
P(A|B)=4/11.
P(A|"\\overline{B}")=m/n,
3 red balls in the bag B, so m=3,
Bag B consists of 10 balls, so n=10+1=11.
P(A|"\\overline{B}")=3/11.
P(A)=4/11"\\cdot"1/10+3/11"\\cdot"9/10=31/90.
The probability of having a red ball eventually is equal 31/90.
b)
Let A be the event that the students in Malaysia use ClassWiz Calculator.
10%/100%=1/10.
P(A)=1/10.
Let B be the event that the students in Singapore use ClassWiz Calculator.
30%/100%=3/10.
P(B)=3/10.
Let C be the event of having a student who uses ClassWiz Calculator eventually.
"P(C)=1-P(\\overline{C})"
"P(\\overline{C})"="P(\\overline{A})P(\\overline{B})"
"P(\\overline{A})=1-P(A)=1-1\/10=9\/10"
"P(\\overline{B})=1-P(B)=1-3\/10=7\/10"
"P(C)=1-9\/10\\cdot7\/10=1-63\/100=37\/100"
The probability of having a student who uses ClassWiz Calculator eventually is equal 37/100.
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