Solution:
(a)
The sum of all probability is 1.
So,
P(X=1)+P(X=2)+P(X=3)+P(X=4)=1.
1/3+1/3+k+1/4=1.
11/12+k=1.
k=1/12.
P(X=3)=1/12.
(b) P(X≤3)= P(X=1)+P(X=2)+P(X=3)
P(X≤3)=1/3+1/3+1/12
P(X≤3)=3/4
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