These reaction times (in tenths of a second) were recorded for group of subjects after each had been given in a drug pain.
Drug A Drug B Drug C
4 9 8
7 11 6
6 12 7
3 8 6
4 10 5
3 11 7
1. Formulate the H0, and H1:
2. C.V. at alpha .01 level of significance
3. Compute the test value: ANOVA - F ratio
4. Decision
5. Interpretation
The total sample size is N=18.
N=18. Therefore, the total degrees of freedom are:
dftotal=18-1=17
Also, the between-groups degrees of freedom are dfbetween=3-1=2, and the within-groups degrees of freedom are:
dfwithin=dftotal-dfbetween=17-2=15
"\\displaystyle\\sum_{i,j}x_{ij}=27+61+39=127"
"\\displaystyle\\sum_{i,j}x_{ij}^2 =135+631+259=1025"
"SS_{total}=\\displaystyle\\sum_{i,j}x_{ij}^2-{1\\over N}(\\displaystyle\\sum_{i,j}x_{ij})^2=1025-{127^2\\over 18}=128.944"
"SS_{within}=\\displaystyle\\sum SS_{within\\ groups}\n=13.5+10.833+5.5=29.833"
"MS_{between}={SS_{between}\\over df_{between}}={128.944-29.833\\over 2}=49.556; \nMS_{within}={SS_{within}\\over df_{within}}={29.833\\over 15}=1.989"
"F=\\dfrac{MS_{between}}{MS_{within}}=\\dfrac{49.556}{1.989}=24.916"
The following null and alternative hypotheses need to be tested:
"H_0:\\mu_1=\\mu_2=\\mu_3"
H1: Not all means are equal
The above hypotheses will be tested using an F-ratio for a One-Way ANOVA.
Based on the information provided, the significance level is "\\alpha" =0.01,
and the degrees of freedom are df1=2, df2=2, therefore, the rejection region for this F-test is R="\\{F: F>F_C=6.359\\}"
Since it is observed that F=24.916>6.359=FC,
, it is then concluded that the null hypothesis is rejected. Therefore, there is enough evidence to claim that not all 3 population means are equal, at the α =0.01
significance level.
Using the P-value approach: The p-value is p=0, using table and since p=0<0.01, it is concluded that the null hypothesis is rejected. Therefore, there is enough evidence to claim that not all 3 population means are equal, at the α =0.01significance level.
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