Question #125708

How many tosses of a fair coin are needed so that the probability of getting atleast one head is 0.875?


Expert's answer

Solution.

Let p=0.875p = 0.875 be the probability of getting at least one head. Let qq be the probability of getting all tails. It is logical that p+q=1.p + q = 1. The coin is fair, so after tossing nn times the probability of of getting all tails is q=0.5nq = 0.5^n. So we get the equation:


0.875+0.5n=1⟹n=log⁡0.5(1−0.875)=30.875+0.5^n = 1 \quad \Longrightarrow \quad n = \log_{0.5}(1-0.875) = 3


Answer: 3


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