"(i)P(x=0)=C_{0}^{4}(0.2)^{0}(0.8)^{4}=0.4096\\\\\n(ii)P(x\\geq3)=P(x=3)+P(x=4)\\\\\n=C_{3}^{4}(0.2)^{3}(0.8)^{1}+C_{4}^{4}(0.2)^{4}(0.8)^{0}=0.0272\\\\"
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