Suppose the student finishes the exam at time "t."
The 1conditional probability that the full time is used will be
"=\\dfrac{P(t>2)}{P(t>1.75)}=\\dfrac{1-P(t\\leq2)}{1-P(t\\leq1.75)}="
"=\\dfrac{1-2\/3}{1-1.75\/3}=0.8"
b. There are 4 choices per question, and 7 questions. So there are
ways to answer.
What is the probability that two papers have the same answer to the first question?
What is the probability that two papers have the same answers ?
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