"Let\\;\\hat p=\\frac{37}{577}=0.064, p_{0}=0.04,n=577\\\\\na) H_{0}: p \\geq 0.04\\\\\nH_{1}: p < 0.04\\\\\n Z_{\u03b1}=Z_{0.01}=2.326,\\\\\nZ=\\frac{\\hat p -p_{0}}{\\sqrt{\\frac{ p_{0}(1-p_{0})}{n}}}\\\\\n=\\frac{0.064 -0.04}{\\sqrt{\\frac{0.04(0.96)}{577}}}=2.94\\\\\n\\text{the rejection region} :\\; Z<-2.326\\\\\n\\text{The decision is to accept}:\\; H_0\\\\\n\\text {This mean that the actual }\\\\\n\\text{percentage is more than or equals 0.04. }\\\\"
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