Question #120453
The survival time, in weeks, of a component X follows an exponential distribution with
parameter β = 5. (i)What is the probability that the survival time will exceed 10 weeks? (ii) What is the conditional probability that the component will survive at least 8 weeks given that it is working at the end of 3rd week? (iii) What is probability that the component will survive between 6 and 12 weeks?
1
Expert's answer
2020-06-08T20:24:18-0400

Given XExp(β),β=5X\sim Exp(\beta), \beta=5


f(x;β)={1βexβ x00otherwisef(x;\beta)= \begin{cases} {1\over \beta}e^{-{x\over \beta}} &\ x\geq 0 \\ 0 &\text{otherwise} \end{cases}

P(X>t)=etβP(X>t)=e^{-{t\over \beta}}


(i)What is the probability that the survival time will exceed 10 weeks?


P(X>10)=e105=e20.135335P(X>10)=e^{-{10\over 5}}=e^{-2}\approx0.135335

(ii) What is the conditional probability that the component will survive at least 8 weeks given that it is working at the end of 3rd week?


P(X8X3)=P(X83)=P(X5)=P(X\geq8|X\geq3)=P(X\geq8-3)=P(X\geq 5)=

=e55=e10.367879=e^{-{5\over 5}}=e^{-1}\approx0.367879

(iii) What is probability that the component will survive between 6 and 12 weeks?


P(6<X<12)=1P(X12)(1P(X6)=P(6<X<12)=1-P(X\geq 12)-(1-P(X\geq6)=

=P(X6)P(X12)=e65e1250.210476=P(X\geq6)-P(X\geq12)=e^{-{6\over 5}}-e^{-{12\over 5}}\approx0.210476


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