Given X∼Exp(β),β=5
f(x;β)={β1e−βx0 x≥0otherwise
P(X>t)=e−βt
(i)What is the probability that the survival time will exceed 10 weeks?
P(X>10)=e−510=e−2≈0.135335
(ii) What is the conditional probability that the component will survive at least 8 weeks given that it is working at the end of 3rd week?
P(X≥8∣X≥3)=P(X≥8−3)=P(X≥5)=
=e−55=e−1≈0.367879 (iii) What is probability that the component will survive between 6 and 12 weeks?
P(6<X<12)=1−P(X≥12)−(1−P(X≥6)=
=P(X≥6)−P(X≥12)=e−56−e−512≈0.210476
Comments