Giventhat,μ=210,σ=56,then,1)P(x>300)=P(Z>56300−210)=P(Z>1.61)=0.5−P(0<Z<1.61)=0.5−0.4463=0.05372)P(x>100)=P(Z>56100−210)=P(Z>−1.96)=0.5+P(0<Z<1.96)=0.5+0.4750=0.97503)P(150<x<250)=P(56150−210<Z<56250−210)=P(−1.07<Z<0.71)=P(0<Z<1.07)+P(0<Z<0.71)=0.3577+0.2611=0.6188
Comments