A question has 5 possible choices out of which only one choice is correct. So, probability of choosing the correct answer , p=1/5=0.2
Since there are total 10 questions, n=10
Let X be the number of correct answers.
Then X follows Binomial distribution with n=10 and p=0.2
P(X=x)="\\binom{n}{x} p^x (1-p)^{(n-x)}"
Probability that at least six questions are correct will be
P(X "\\geq6)"=P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)
="\\binom{10}{6}(0.2)^6(1-0.2)^4 +"
"\\binom{10}{7}(0.2)^7(1-0.2)^3 +"
"\\binom{10}{8}(0.2)^8(1-0.2)^2+" "\\binom{10}{9}(0.2)^9(1-0.2)^1+" "\\binom{10}{10}(0.2)^{10}(1-0.2)^0"
= 210.(0.00026) + 120.(0.0000065)+ 45(.0000016) + 10.(.00000041) + 1.(0.2)10
=0.006369
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