Question

Suppose Komla throws a die repeatedly until he gets a six. What is the probability
that he needs to throw more than 10 times to get a six, to 3 decimal places

Answer 1

The event we are after is equivalent to "no six on the first 10 rolls". Since this requires any number other than 6 on the first roll (p=5/6), any number other than 6 on the second roll, etc the probability is

P=(5/6)¹⁰=0.162