Question

Raymond is a basketball player who takes four independent free throws with 70% probability of getting a basket on each shot. Let X be the number of baskets Raymond gets. Find the probability that he gets exactly 2 baskets, to 3 decimal places.

Answer 1

The probability that he does not get a basket is $1-0.7 =0.3;$

There are 6 different cases here: hit, hit, no, no;hit,no,hit,no;and so on. The main thing is that all these cases are equally probable consider any of them.

$hit, hit, no, no;\;0.7\times0.7\times0.3\times0.3=0.0441.$

there may be 6 such cases in total, so

$P=0,0441\times6=0.265$

Answer: 0.265