Question #119098

there are 20 people in a room singing. the mean age of 12 of the members is 18years. the mean age of the remaining 8 is 23 years. what is the mean age of the 20 members of the singing group

Expert's answer

mean=μ=i=1nxinmean=\mu={\displaystyle\sum_{i=1}^nx_i\over n}

The mean age of 12 of the members is 18 years:


μ1=i=112xi12=18\mu_1={\displaystyle\sum_{i=1}^{12}x_i\over 12}=18i=112xi=12(18)=216\displaystyle\sum_{i=1}^{12}x_i=12(18)=216

The mean age of the remaining 8 is 23 years:


μ2=i=1320xi8=23\mu_2={\displaystyle\sum_{i=13}^{20}x_i\over 8}=23i=1320xi=8(23)=184\displaystyle\sum_{i=13}^{20}x_i=8(23)=184

What is the mean age of the 20 members of the singing group?


μ=i=120xi20=i=112xi+i=1320xi20=\mu={\displaystyle\sum_{i=1}^{20}x_i\over 20}={\displaystyle\sum_{i=1}^{12}x_i+\displaystyle\sum_{i=13}^{20}x_i\over 20}=

=216+18420=20={216+184\over 20}=20

 The mean age of the 20 members of the singing group is 20 years.



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