(a) P(x)=C96x(132)x(3132)96−xP(x)=C_{96}^x (\frac{1}{32})^x(\frac{31}{32})^{96-x}P(x)=C96x(321)x(3231)96−x
(b) Using the Poisson approximation with λ=np=96∗132=3.\lambda=np=96*\frac{1}{32}=3.λ=np=96∗321=3.
P(X≤1)=P(X=0)+P(X=1)=e−λ+λe−λ=e−3+3e−3=0.1991.P(X\le1)=P(X=0)+P(X=1)=e^{-\lambda}+\lambda e^{-\lambda}=e^{-3}+3e^{-3}=0.1991.P(X≤1)=P(X=0)+P(X=1)=e−λ+λe−λ=e−3+3e−3=0.1991.
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A random variable X has the cumulative distribution function given as F(x) = 0, for x < 1 x2 −2x + 2 2 , for 1 ≤ x < 2 1, for x ≥ 2 Calculate the variance of X.
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Dear Nyarko Richard, please use the panel for submitting new questions and type math formulas neatly so that experts could identify them correctly.
A random variable X has the cumulative distribution function given as F(x) = 0, for x < 1 x2 −2x + 2 2 , for 1 ≤ x < 2 1, for x ≥ 2 Calculate the variance of X.