H1={from Japan}; p(H1)=0.2
H2={from neighbouring countries}; p(H2)=0.8
A={1 is ineffective from 30 randomly selected}
"p(H_1\/A)=\\frac{p(A\/H_1)p(H_1)}{p(A\/H_1)p(H_1)+p(A\/H_2)p(H_2)}"
"p(A\/H_1)=C_{30}^1(0.1)(0.9)^{29}=0.1413"
"p(A\/H_2)=C_{30}^1(0.02)(0.98)^{29}=0.334"
"p(H_1\/A)=\\frac{0.1413*0.2}{0.1413*0.2+0.8*0.334}=0.096"
Answer: 0.096.
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