H1={from Japan}; p(H1)=0.2
H2={from neighbouring countries}; p(H2)=0.8
A={1 is ineffective from 30 randomly selected}
p(H1/A)=p(A/H1)p(H1)+p(A/H2)p(H2)p(A/H1)p(H1)
p(A/H1)=C301(0.1)(0.9)29=0.1413
p(A/H2)=C301(0.02)(0.98)29=0.334
p(H1/A)=0.1413∗0.2+0.8∗0.3340.1413∗0.2=0.096
Answer: 0.096.
Comments