A machine elastic bands with breaking tension normally distributed with mean 45 N and standard deviation 4.36 N.
a. In order to test whether there is a change in the mean breaking tension, a random
sample of 50 was tested and found to have a mean breaking tension of 43.46 N.
i. Determine a 95% confidence interval for the population mean breaking tension
based on the sample mean assuming an unchanged standard deviation.
1
Expert's answer
2020-04-23T18:25:14-0400
Sample mean=43. 46N
Population standard deviation =4.36N
95% CI ="\\bar x\u00b1Z_c \\frac {\\sigma} {\\sqrt n}"
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