Question #109625
6.7 In 2014, the per capita consumption of bottled water in Spain was recorded to be 32.1 gallons. (Data obtained from http://bit .ly/1pyjHzQ.) Assume that the per capita consumption of bottled water in Spain is approximately normally distributed with a mean of 32.1 gallons and a standard deviation of 8 gallons.
1
Expert's answer
2020-04-15T11:57:43-0400

Let X=X= the number of consumed of bottled water: XN(μ,σ2).X\sim N(\mu, \sigma^2).

Then Z=XμσN(0,1)Z=\dfrac{X-\mu}{\sigma}\sim N(0,1)

Given: μ=32.1,σ=8.\mu=32.1, \sigma=8.

a.The probability that someone consumed more than 32 gallons of bottled water is


P(X>32)=1P(X32)=P(X>32)=1-P(X\leq 32)=

=1P(Z3232.18)=1P(Z0.0125)=1-P(Z\leq {32-32.1 \over8})=1-P(Z\leq -0.0125)\approx

0.504987\approx0.504987

b. The probability that someone consumed between 25 and 35 gallons of bottled water is


P(25<X<35)=P(X<35)P(X<25)=P(25<X<35)=P(X<35)-P(X<25)=

=P(Z<3532.18)P(Z<2532.18)==P(Z<{35-32.1 \over8})-P(Z< {25-32.1 \over8})=

=P(Z<0.3625)P(Z<0.8875)=P(Z<0.3625)-P(Z<-0.8875)\approx

0.64151080.18740490.454106\approx0.6415108-0.1874049\approx0.454106

c. The probability that someone consumed less than 25 gallons of bottled water is


P(X<25)=P(Z<2532.18)=P(X<25)=P(Z< {25-32.1 \over8})=

P(Z<0.8875)0.187405P(Z<-0.8875)\approx0.187405

d. 99 % of people consumed less than how many gallons of bottled water?


P(X<X)=P(Z<X32.18)=0.99P(X<X^*)=P(Z<{X^*-32.1 \over8})=0.99

X32.182.32635{X^*-32.1 \over8}\approx2.32635

X50.710851X^*\approx50.7108\approx51


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