Question #109253
In a certain government office, there are 400 employee, there are 150 men, 276 University graduates, 212 married persons, 94 male University graduates, 151 married university graduates, 119 married men, 72 married male graduates. Find the number of single women who are not University graduates.
1
Expert's answer
2020-04-13T19:24:27-0400

Let UU be set of all employees, MM - men, AA - university graduates, BB - married persons.

We know that U=400, M=150, A=276, B=212|U|=400, \ |M|=150, \ |A|=276, \ |B|=212

MAM \cap A - male university graduates, MA=94|M\cap A| =94

ABA\cap B - married university graduates, AB=151|A\cap B|=151

MBM\cap B - married men, MB=119|M\cap B| =119

MABM\cap A\cap B - married male graduates, MAB=72| M\cap A\cap B|=72

We need to find the number of single women who are not university graduates.

So, these persons aren’t men, aren’t married and aren’t university graduates.

Set of of single women who are not university graduates can be represented as MABM ^\prime \cap A ^\prime \cap B ^\prime . Now we will find MAB|M ^\prime\cap A ^\prime\cap B ^\prime | .

MAB=(MAB)M ^\prime\cap A ^\prime \cap B ^\prime =(M\cup A\cup B) ^\prime (It is De Morgan's law)

MAB=(MAB)=UMAB|M ^\prime\cap A ^\prime\cap B ^\prime|=|(M\cup A\cup B) ^\prime|=|U|-|M\cup A \cup B|

MAB=M+A+BMAABMB+MAB|M\cup A\cup B|=|M|+|A|+|B|-|M\cap A|-|A\cap B|-|M\cap B|+|M\cap A\cap B|

( It is inclusion–exclusion principle )

MAB=150+276+21294151119+72=346|M\cup A\cup B|=150+276+212-94-151-119+72=346

UMAB=400346=54|U|-|M\cup A\cup B|=400-346=54


Answer: there are 54 single women who are not University graduates.


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