Question #264639

Prove that the sum of two convergent sequence is convergent.

1
Expert's answer
2021-11-16T11:21:57-0500

Let A and B be the points of convergence of the two respective series. The convergence of the two series implies that given any ε>0\varepsilon>0 , there exists an integer N0N_{0} such that for any NN0N \geq N_{0} , we have

An=1Nan<εBn=1Nbn<ε\begin{aligned} &\left|A-\sum_{n=1}^{N} a_{n}\right|<\varepsilon \\ &\left|B-\sum_{n=1}^{N} b_{n}\right|<\varepsilon \end{aligned}

We claim that n=1an+bn2\sum_{n=1}^{\infty} \frac{a_{n}+b_{n}}{2} converges to A+B2\frac{A+B}{2} . Indeed, for all NN0N \geq N_{0} , we can use the triangle inequality to get

A+B2n=1Nan+bn212An=1Nan+12Bn=1Nbn<ε\left|\frac{A+B}{2}-\sum_{n=1}^{N} \frac{a_{n}+b_{n}}{2}\right| \leq \frac{1}{2}\left|A-\sum_{n=1}^{N} a_{n}\right|+\frac{1}{2}\left|B-\sum_{n=1}^{N} b_{n}\right|<\varepsilon

Hence, the sum of two convergent sequence is convergent.


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