Let f(z) be an analytic function in the annulus 0 <|z| < R for some positive real number R,Whose laurent series (in this annulus) is given by
f(z) = n from -∞ to ∞ ∑ { (-1)^n / (n^2)! ] } . Z ^ { 5n - n^2 -1}
A)) What Kind of Singularity is z=0 for f(z) ?
B)) Compute integral on Curve for [ z ^ 24 . f(z) dz] ,where C is a counterclockwise simple path lying in the annulus enclosing z=0
C)) Calculate Res (f) in z=0
D)) Evaluate Integral on Curve for [ sin Z .f(z) dz] , where C : |z| = (R/2) oriented counterclockwise
Note : please not by limit
Let f(z) be an analytic function in the annulus 0 <|z| < R for some positive real number R,Whose laurent series (in this annulus) is given by
f(z) = n from -∞ to ∞ ∑ { (-1)^n / (n^2)! ] } . Z ^ { 5n - n^2 -1}
A)) What Kind of Singularity is z=0 for f(z) ?
B)) Compute integral on Curve for [ z ^ 24 . f(z) dz] ,where C is a counterclockwise simple path lying in the annulus enclosing z=0
C)) Calculate Res (f) in z=0
D)) Evaluate Integral on Curve for [ sin Z .f(z) dz] , where C : |z| = (R/2) oriented counterclockwise
Note : please not by limit
If P(x,n)= F(x,n)+F(x^2,n)+ F(x^3,n)+……+ F(x^n,n) where F(x, n)= x mod n, (i.e.
12 Mod 5 = 2 , means if we divide 12 by 5 we get a remainder of 2)
How many values of n are there so that, P(2014,n)=n ,where n<2012?
for each matrix, state te maximin for player 1(the row player). State the minimax for player 1(the column player). Is there a saddlepoint? does either player do better than their strategy?
A car hire company has one car at each of five depost a, b,c,d,e.a customer requires a car in each town namely A,B,C,D,E distances between deposits and town are given in the following distance matrix how should the cars be assigned so as to minimize the distance travelled
a. b. c. d. e
A. 160. 130. 175. 190. 200
B. 135 120. 130. 160 175
C. 140. 110. 155. 170. 185
D. 50. 50. 80. 80. 110
E. 55. 35. 70. 80. 105
This is a Logic question. I need the proof of the argument...... 1. A v ~B 2. ~A v S // B -> S.
I am not sure if the answer 3.com .impl. 5.impl. 6.hs is correct.